-2x^2+24x-40=24

Solution for -2x^2+24x-40=24 equation:

-2x^2+24x-40=24

We move all terms to the left:

-2x^2+24x-40-(24)=0

We add all the numbers together, and all the variables

-2x^2+24x-64=0

a = -2; b = 24; c = -64;
Δ = b2-4ac
Δ = 242-4·(-2)·(-64)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8}{2*-2}=\frac{-32}{-4}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8}{2*-2}=\frac{-16}{-4}
=+4
$